Normality (N) is another way to quantify solution concentration. It is similar to molarity but uses the gram-equivalent weight of a solute in its expression of solute amount in a liter (L) of solution, rather than the gram molecular weight (GMW) expressed in molarity. A 1N solution contains 1 gram-equivalent weight of solute per liter of solution.
Expressing gram-equivalent weight includes the consideration of the solute's valence. The valence is a reflection of the combining power of an element often as measured by the number of hydrogen atoms it can displace or combine with. A 1.0 gram-equivalent weight is the amount of a substance that will combine with or displace 1 atom of hydrogen.
To determine gram-equivalent weight of a substance:
Divide the GMW of a solute by the valence (number of hydrogen ions that can be displaced).
Example:
The normality of a 1.0 liter NaCl solution that contains 1.0 gram-equivalent weight will be the GMW of NaCl divided by the valence of NaCl:
(Atomic weights of Na = 22.99 and Cl = 35.45)
GMW of NaCl = 22.99 + 35.45 = 58.44 g
N = GMW/valence (the valence for NaCl is 1.0)
58.44 g/1.0 = 58.44 g = 1.0 gram-equivalent weight of NaCl = 1N solution of NaCl
In this situation, because NaCl has a valence of one, the molarity and normality of the solution are the same. Some compounds, however, will not have the same normality as molarity, as in the case of H2SO4.
Example:
The normality of a 1.0 liter solution of H2SO4 containing 1.0 gram-equivalent weight will be the molecular weight of H2SO4 divided by the valence of H2SO4:
(Atomic weights of H = 1, S = 32.06, and O = 16)
GMW of H2SO4 = 1(2) + 32.06 + 16(4) = 98 g
N = GMW/valence (the valence for H2SO4 is 2.0, as there are 2.0 H ions that could be displaced)
98 g /2 = 49 g = 1.0 gram-equivalent weight of H2SO4 = 1N solution of H2SO4
The molarity of this 1N solution of H2SO4 would be 0.5 (M = g /GMW per liter or 49g/98g = 0.5)
To simply calculate the amount or weight of a substance needed for a desired normal solution, the following formula may be used:
Weight in grams = desired normality × volume needed in liters × GMW/valence
(W = N × V × GMW/valence)
Example:
500 mL of a 0.1N solution of NaOH is needed for a procedure. Calculate the amount of solute (NaOH) needed to prepare the solution. (Atomic weights: Na = 22.99; O = 16; H = 1) Valence = 1
X g= 0.1N × 500 mL (0.5 L) × GMW 39.99 / 1.0
X = 0.1 x 0.5 × 39.99/1.0
X = 1.99
1.99 g of NaOH must be diluted to 500 mL to prepare a 0.1N solution.